Trapezoid pqrs is rotated 180° about the origin to form trapezoid p'q'r's'. which statement is true? a) the sum of the angle measures of trapezoid pqrs is 180° less than the sum of the angle measures of trapezoid p'q'r's'. b) trapezoid pqrs is not congruent to trapezoid p'q'r's'. c) the area of trapezoid pqrs is less than the area of trapezoid p'q'r's'. d) the angle measures of trapezoid pqrs are equal to the corresponding angle measures of trapezoid p'q'r's'.

D)The angle measures of trapezoid PQRS are equal to the corresponding angle measures of trapezoid P'Q'R'S'

Step-by-step explanation:

Since, By the definition of rotation about origin, When a figure is rotate 180° about the origin then we get a congruent figure to that figure.

Thus, when PQRS is rotated 180° about the origin to form trapezoid P'Q'R'S'.

Then trapezoid P'Q'R'S' is congruent to trapezoid PQRS.

⇒  By the definition of congruence,

The corresponding sides and angle of trapezoid P'Q'R'S' are congruent to that of trapezoid PQRS.

⇒ ∠P' ≅ ∠P, ∠Q' ≅ ∠Q, ∠R' ≅ ∠R and  ∠S' ≅ ∠S

⇒ Option D) is correct.

Note:  P'Q'R'S' is a trapezoid ⇒ Sum of the angle measures of trapezoid P'Q'R'S' is also 180°

Option A) is incorrect.

Since, trapezoid P'Q'R'S' is congruent to trapezoid PQRS.

⇒ Option B) is incorrect.

We know that if two shapes are congruent then their area must be equal.

⇒ Area of trapezoid P'Q'R'S' = Area of trapezoid PQRS

Thus, Option C) is also incorrect.

the anwer is D

Step-by-step explanation:

youre welcome

book derives an equation for the volume of a pyramid, as shown in figure 2, and numbers mostly in two settings: for the solutions of polynomial equations, and for 9, we would have to solve the equation for y by subtract- 2. the point (1,. 2) is the center of the circle whose equation is x2 y2. 2x. 4y p.w.c. davies.

step-by-step explanation:

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

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step-by-step explanation: