Daniel spent 2/5 of his money on books, 1/3 of the remaining money on food and he has left with $28. how much money did he have before the shopping?

Step-by-step explanation:

Let us assume that Daniel had total money before shopping = $x.

He spent  of total money on books, that is = $  of x=  x.

Remaining money with him = (x- x) .

And spent 1/3 of the remaining that is 1/3 of (x-2/5x)  = 1/3(x- x) on food.

Money left with him = $28.

Therefore, we can setup and equation.

Money spent on books + Money spent on food + Remaining money = Total money  before shopping.

Substituting above values in equation, we get

 x +   (x- x) + 28 = x.

Subtracting x- x = - = , we get

x +  () + 28 = x.

Multiplying (), we get

Therefore,

x ++28=x

x +28 =x.

Subtracting on both sides, we get

x + 28- x =x- x

28 =   -

28 = .

Multiplying both sides by 5, we get

28×5 = 5×.

140 =2x.

Dividing both sides, by 2, we get

x=70.

6x = 48

i hope this . 6 cards each and a total of $48. dvide each side by 6 and you will have your answer.