Iwill award in the figure, what is n in terms of m and p? a. m+p+180° b. 180°−p+m c. 360°+m−p d. 360°−m+p

The 3 outside angles of a triangle need to equal 360 degrees.

So you have n + m + p = 360

So to find n, you would add m and p together and subtract that from 360.

Without parenthesis I do not see a correct choice.

The answer should be 360 - (m+p)

The closest answer to this is D.

B. 180°−p+m  

Step-by-step explanation:

The angle on the other side of n, call it N, is 180 - n

N = 180 -n

The angle on the other side of p, call it P, is 180 - p

P = 180 -p

The angle inside the triangle opposite m is the same as m because it is a vertical angle and vertical angles are equal.

We are looking to find the angles inside the triangle, because we know they add to 180 degrees  

N+P+m = 180

(180-n) + (180-p) +m = 180

Combine like terms

360 -n-p+m = 180

Add n to each side

360 -n+n-p+m = 180+n

360 -p+m = 180+n

Subtract 180 from each side

360-180 -p+m =180-180+n

180+m-p =n

y do u put "subscirbe to ence" on a app for ppl who need with their work?

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!