Find the range of y = 3/2 cos 4x - 1i tried it and i got an answer of -1/2 < = y < = 3/ but this is not one of the choices! choices: a) -1/2 < = y < = 1/2b) -2 1/2 < = y < = 1/2c) -3/2 < = y < =3/2d) -5 < = y < =3

B.

Step-by-step explanation:

The given trigonometric function is

.

The amplitude of this function is , so under normal circumstances the range is supposed to be

But the is a downward vertical shift.

Therefore the normal boundaries  of the range will shift down one unit to give the range of the transformed function.

We subtract 1 from the lower boundary to get

We also subtract 1 from the upper boundary to get

Hence the range is

Also see graph

Did you get there answer to 44?

1. isolate the variable, in this case, d. subtract 35.5 on both sides of the equation.2. 52 subtracted by 35.5 is 16.53. therefore your answer would be d= 16.5this is the basics of pre algebra, isolating variable through adding, subtracting, multiplying, and dividing, if you have any other questions to ask just comment!