Which values are solutions to the inequality –3x – 4 < 2? check all of the boxes that apply. -4-203*answer is 0 and 3*

0 and 3 are solution of inequality.

Step-by-step explanation:

Given  : -3x – 4 < 2.

To find : Which values are solutions to the inequality.

Solution : We have given

-3x – 4 < 2.

For x = -4 .

-3 ( -4) -4 < 2 .

12 -4< 2.

8 < 2

Which is false statement .

For x = -2 .

-3 ( -2) < 2

6 < 2

This is false statement so, this is not the solution of inequality .

For x = 0 .

3( 0) -4 < 2 .

-4 < 2

We know that negative value is always less than positive .

So, x = 0 is solution of inequality.

For x = 3

-3 ( 3) - 4 < 2

-9 - 4 < 2

-13 < 2

This is also he solution of inequality.

Hence there are two solution 0 ,3.

Therefore,  0 and 3 are solution of inequality.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2