How do you substitute 3x-12y=-6 and x-4=-8?

x - 4 = -8      add 4 to both sides

x = -4

Put the value of x to the first equation 3x - 12y = -6:

3(-4) - 12y = -6

-12 - 12y = -6         add 12 to both sides

-12y = 6       divide both sides by (-12)

y = - 0.5

New question:

x - 4y = -8       add 4y to both sides

x = 4y - 8

Substitute it to the first equation:

3(4y - 8) - 12y = -6       use distributive property

(3)(4y) + (3)(-8) - 12y = -6

12y - 24 - 12y = -6

-24 = -6     FALSE

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3