What is the y-intercept of y = 2/3x + 2 a) (2, 3) b) (3, 2) c) (0, 2) d) (-3, 0)

C) (0, 2)

Step-by-step explanation:

y = 2/3x + 2

This is in the form y = mx+b

b is the y intercept  

We have the y intercept when x=0

(0,b)

(0,2)

C) (0, 2) is your answer

Step-by-step explanation:

Note the equation:

y = mx + b  is the equation used in y = (2/3)x + 2

m is the slope ; b is the y-intercept.

You are solving for the y -intercept, which is b. b = 2, therefore, 2 is your y.

Also note that when you are solving for the y-intercept, x must = 0 (& vice versa for when you are solving for x -intercept.)

~

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: