During the first hour of operation the farm stand owner sold 15% of the apples he had. on the second hour he sold 20% of the remaining apples. on the third hour he sold 25% of the remaining apples, and so on, selling 5% more each following hour, if during the second hour 25.5 kg of apples were sold, how many kilograms of apples will be sold during the fourth hour of operation?

 3.825 kg apples.

Step-by-step explanation:

Let x kg be the amount of apples stand owner had initially.

We have been given that during the first hour of operation the farm stand owner sold 15% of the apples he had. Then the amount of sold apples will be:

On the second hour he sold 20% of the remaining apples. So the amount of sold apples on the second hour will be 20% of 0.85x.

During the second hour 25.5 kg of apples were sold, so we can set up an equation as:

So, stand owner had initially 150 kg of apples.

On the third hour he sold 25% of the remaining apples. So the amount of sold apples on the 3rd hour will be 25% of 0.68x

As remaining apples were sold 5% more each following hour.

Let us substitute x=150 into above equation we will get,

Therefore, 3.825 kg of apples were sold during the 4th hour.

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.

idk man good luck man