Kay was walking along the bridge above the river. she accidentally lost her grip on her camera when she was trying to get it out to photograph a massive bird nest in the trees. the height of the camera above the water can be modeled by the equation y=16t^2+400, where t represents the seconds after the camera is dropped. how long will it take before kay sees the splash from the camera hitting the water

y = -16 t^2 + 400

Step-by-step explanation:

We can see

that the slope of the equation is negative (-16) which means that the position

of Kay is on the positive y-axis , while the bottom of the river is in the

origin. This is supported by taking t = 0, the initial y becomes y = 400.

Therefore the position of Kay now is at (0, 400).

So to find

for the time when the camera hits the water, then y must be zero (t, 0) so we

have to find for t in this case.

When y = 0

0 = -16 t^2

+ 400

16 t^2 = 400

t^2 = 25

t = 5 s

Therefore it

takes 5 seconds for the camera to hit the water and for Kay to see a splash.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation: