How to find the polar coordinates of (3, π/2)

Rectangular coordinates , (x, y) = (0 , 3)

Step-by-step explanation:

We have given,

Polar coordinates , (r , Θ) = (3 , π/2)

We need to find corresponding rectangular coordinates.

Since, x = rcosΘ and y = rsinΘ

Here r = 3  and Θ = π/2

So, x = 3cosπ/2 = 3×0 = 0  ∵ cosπ/2 = 0

And y = 3sinπ/2 = 3×1 = 3   ∵ sinπ/2 = 1

Hence rectangular coordinates of given polar coordinates is ( 0 , 3)

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.