Triangles abc and dbc have the following characteristics: bc is a side of both triangles ∠acb and ∠dcb are right angles ac ≅ dc which congruence theorem can be used to prove △abc ≅ △dbc?

LL

Step-by-step explanation:

You are given two congruent legs: BC≅BC and AC≅DC. The fact that it is a right triangle lets you invoke the LL theorem of congruence for right triangles. (This is a special case of the SAS theorem, where the A is 90°.)

SAS congruence postulate

Step-by-step explanation:

Given : Triangles ABC and DBC have the following characteristics:

BC is a side of both triangles

∠ACB and ∠DCB are right angles

AC ≅ DC

Using the given information , we have made the following diagram.

Now, in ΔABC and ΔDBC

BC= BC    [By Reflexive property]

∠ACB and ∠DCB= 90°            [Measure of right angle = 90°]

AC ≅ DC                   [Given ]

So by SAS congruence postulate , we have

ΔABC ≅ ΔDBC

28

step-by-step explanation:

8+8+6+6

b

step-by-step explanation: