Aflat screen tv is measured by its diagonal length. you have enough space to fit a tv that is 25 inches wide and 20inches tall. the diagonal of the tv measures 32 inches and it is 19.2 inches tall. how wide is the tv? can you fit a 32”tv in your space? explain

The tv is too big

Step-by-step explanation:

Using the Pythagorean theorem

a^2 +b^2 =c^2

where a and b are the legs of the triangle and c is the hypotenuse

We know the diagonal or hypotenuse is 32 and one of the legs is 19.2  so we can find the other leg

a^2 + 19.2 ^2 = 32 ^2

a^2 + 368.64 =1024

Subtract 368.64 from each side

a^2 + 368.64-368.64 - 368.64 =1024-368.64

a^2 =655.36

Take the square root of each side

sqrt(a^2) = sqrt(655.36)

a =25.6

The dimensions of the space are 20 by 25

Our TV is 19.2 by 25.6   The TV is too long by (25.6-25=.6)  by .6 inches

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

10 you would take 50/ .2

step-by-step explanation: