Ineed with number 18 & 20 i did them but idk if they are right.

18. (x, y) ∈ {(-2, -11), (0, -3)}

20. x < 3; x² -1 < y < x² -x +2

Step-by-step explanation:

18. Equate the values of y, then solve for x.

... 4x -3 = -x^2 +2x -3

... x^2 +2x = 0

... x(x +2) = 0

The values of x that make these factors zero are ...

... x = 0, x = -2

The corresponding values of y are ...

So, the solutions are (x, y) = (0, -3) or (-2, -11).

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20. This can be worked the same way to find a range of x that will make the system of equations true. The range of y must be computed based on that.

... x^2 -1 < y < x^2 -x +2

... x < 3 . . . . . . . . add -x^2 +x +1

The allowed range of y will vary with x, so the solution can be expressed as ...

... x < 3 and x^2 -1 < y < x^2 -x +2

no pictures of the graph

360/29

step-by-step explanation: