Abag of jelly beans contains 10 red,6 green,7 yellow, and 5 orange jelly beans. what is the probability of randomly choosing a red jelly bean, replacing it, randomly choosing another red jelly bean, replacing it, and then randomly choosing an orange jelly bean?

Step-by-step explanation:

No. of red jelly = 10

No. of green jelly = 6

No. of yellow jelly = 7

No. of orange jelly = 5

Total number of jelly = 10 + 6 + 7 + 5 = 28

Hence, the required probability is 0.02 or 2 %

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.

its 4 because 2 times 2 is 4, if you double the number two you get four