The base of an auditorium is in the form of an eclipse 200 feet long and 100 feet wide a pin drop near one focus can clearly be heard at the other focus determine the distance between the foci to the nearest 10th of a how would i work this out? ?

Let the coordinate of focus be

As per the statement: The base of an auditorium is in the form of an eclipse 200 feet long and 100 feet wide.

⇒Length of Major axis=base of an auditorium = 200 feet and Length of a minor axis=wide of a auditorium = 100 ft

Semi-major axis (a) = 100 ft and

semi-minor axis(b) = 50 ft

Then, by an equation:

Solve for c:

Substitute the given values we have;

Simplify:

or

ft

Distance between the foci is,  

Therefore, the distance between the foci to the nearest 10th of a foot is, 173.2 ft

15 units use socratic

step-by-step explanation: 15 units

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!