In right triangle abc, where c is the right angle : b = 12 and b = 33°. find a, a, and c to the nearest tenth.

A= 57° , a= 7.79  and c = 14.30

Step-by-step explanation:

In a given right triangle,

We have, b =12 ,B =33° and C =90°

We can find Angle A.

Angle sum property of triangle:

i.e A + B + C = 180°

A + 33° + 90° = 180°

A = 57°

Next, by using trigonometry

tanB = Perpendicular /Base  = a /b

Here B =33° , a = ? , b = 12

So, tan 33° = a/12

0.6494 = a/12

a = 7.79

So we got a and b. By using Pythagoras theorem we determine c.

c^2 = a^2 + b^2

c^2 = 7.79^2 + 12^2

c = √(2046841) = 14.30

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)