Suppose i have either a fair coin or a bent coin, and i don't know which. the bent coin has a 60% probability of coming up heads. i throw the coin ten times and it comes up heads 8 times. what is the probability i have the fair coin vs. the probability i have the bent coin?

Last part of Question:

Assume at the outset there is an equal (.5,.5) prior probability of either coin.

0.36

Step-by-step explanation:

Let P(A) = Probability of fair coin = 0.5

Let P(B) = Probability of bent coin = 0.5

The coin was thrown 10 times

The number of possible events, E = 10

P(E | A) =

P(E | A) =0.0440

P(E |B) =

P(E |B) = 0.1209

Probability of having the fair coin vs the probability of having the bent coin = 0.2665/0.7334

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.

addition

step-by-step explanation: