Anyone know how to do this? if so plz

NOTES:

Use the equation y = mx + b where m is the unit rate and b is the one-time flat fee

1.

Step-by-step explanation:

coffee maker costs $70 - this is a one-time flat fee

it costs $0.20 per cup of coffee - this is the unit rate

y = 0.20x + 70

y = 0.20(0) + 70   →   y = 0.00 + 70   →   y = 70.00

y = 0.20(1) + 70   →   y = 0.20 + 70    →   y = 70.20

y = 0.20(2) + 70   →   y = 0.40 + 70   →   y = 70.40

y = 0.20(3) + 70   →   y = 0.60 + 70   →   y = 70.40

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2.

Step-by-step explanation:

shoes costs $3.00 - this is a one-time flat fee

it costs $1.50 per game of bowling - this is the unit rate

y = 1.50x + 3.00

y = 1.50(1) + 3.00  →    y = 1.50 + 3.00   →   y = 4.50

y = 1.50(2) + 3.00  →   y = 3.00 + 3.00   →   y = 6.00

y = 1.50(3) + 3.00  →   y = 4.50 + 3.00   →   y = 7.50

y = 1.50(4) + 3.00  →   y = 6.00 + 3.00   →   y = 9.00

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3. Negative

Step-by-step explanation:

As the x-values increase, the y-values decrease.  Opposite directions results in a negative slope.

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4. Gym A → y = 20x + 50    Gym B → y = 25x + 30

Step-by-step explanation:

Use the slope formula: .  Then choose ONE of the points and input the point (x₁, y₁) and slope (m) into the Point-Slope formula: y - y₁ = m(x - x₁) and solve for y.

Gym A: (x₁, y₁) = (1, 70) and (x₂, y₂) = (2, 90)

y - 70 = 20(x - 1)

y - 70 = 20x - 20

y        = 20x + 50

Gym B: (x₁, y₁) = (1, 55) and (x₂, y₂) = (2, 80)

y - 55 = 25(x - 1)

y - 55 = 25x - 25

y        = 25x + 30

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

answer: dead jah

step-by-step explanation:

bullet + jah= dead jah