Answers: 1
![\quad 6^2+\sqrt[3]{125} \\= 6 \cdot 6+\sqrt[3]{5\cdot 5 \cdot 5}\\= 36 + 5\\= 41](/tpl/images/0020/0496/30617.png)
![\bigg(\dfrac{7}{3}\times \sqrt[3]{27}-2\bigg)\times \dfrac{1}{5} + \sqrt{81}](/tpl/images/0020/0496/e9ba0.png)
![=\bigg(\dfrac{7}{3}\times \sqrt[3]{3\cdot 3 \cdot 3}-2\bigg)\times \dfrac{1}{5} + \sqrt{9\cdot 9}](/tpl/images/0020/0496/80309.png)
           ![\sqrt[3]{64}=\sqrt[3]{4\cdot 4\cdot 4}=4](/tpl/images/0020/0496/fa2af.png)
              ![\sqrt[3]{8000}=\sqrt[3]{20\cdot 20\cdot 20}=20](/tpl/images/0020/0496/0dcec.png)
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