Adam has $2.15 in nickels, dimes and quarters in his pocket. if the number of dimes is 4 less than the number of nickels, and 5 more than the number of quarters, then how many of each type of coin does he have?

nickels = 12, dimes = 8, quarters = 3

Step-by-step explanation:

First, set up the equations for each coin:

Next, the sum of the coins is $2.15 so substitute and solve for the variable:

   Nickels         +   Dimes  +     Quarters     =   Sum

0.20 + 0.05d  +    0.10d   +   0.25d - 1.25   =  2.15

           0.40d - 1.05 = 2.15

           0.40d           = 3.20

                  d            = 8

Lastly, plug the d-value into the quantity equation for the nickels and quarters to find their quantity.

nickels: 4 + d   = 4 + (8)   = 12

quarters: d - 5   = (8) - 5   = 3

me! what did you put for this question?

step-by-step explanation: