Question 1: write an equation of the line in slope-intercept form that has a slope of −2 3 and has a y-intercept of -4 question 2: write an equation of a line in slope-intercept form that passes through the points (3, -2) and (1, 4)

y = -2/3(x) - 4; y = -3(x) + 7

Step-by-step explanation:

question 1) y = -2/3(x) - 4 is the equation for this problem because it uses the form y=mx + b, where m is the slope and b is the y-intercept

question 2) to find this equation, we must first find the slope between these two points. To do this, take the y of the second point minus the y of the first point, then divide that by the difference of the x of the second point by the x of the first point.

To simplify: slope (m) = (4 - (-2))/(1-3) = (6)/(-2) = -3

Then to find the y-intercept, plug in one of the points for y and x in the equation, including the slop. The equation for b should be 4 = (-3)(1) + b which then turns out to be = 7.

Then all you do is plug in the slope and y-intercept into the y = mx + b equation and that is your solution.

step-by-step explanation: