Which postulate or theorem proves △fwj∼△pkj ? aa similarity postulate sas similarity theorem sss similarity theorem triangle f w j with right angle w and triangle p k j with right angle k. points w, j, and k are collinear. w j is 10 centimeters and k j is 5 centimeters. angle f j w is labeled 63 degrees and angle j p k is labeled 27 degrees.

AA Similarity Postulate  proves △FWJ∼△PKJ

Step-by-step explanation:

It is given that,

△FWJ and △PKJ are two right angled triangle.

In △FWJ right angled ate W  and in △PKJ right angled at K.

Therefore <W = < K

To find angles of ΔFWJ

In △FWJ , <FJW = 63°  then <WFJ = 90° - 63° = 27°∼△PKJ

To find angles of ΔPKJ

In △PKJ, <JPK = 27° then <PJK = 90°-27° = 63°

According to this information AA Similarity Postulate  proves that

△FWJ∼△PKJ

i'm not entirely sure

step-by-step explanation:

if you ask home depot or lowe's they might be able to you out

45

step-by-step explanation:

to find a percentage, add a decimal in front and multiply it by the other number.

.25 times 180= 45