Suppose the line of best fit is being found for some points that have an r-value of 0.769. if the standard deviation of the x-coordinates is 5.508, what is the slope of the line to three decimal places?

r value i.e Correlation between x value and y value = 0.769

=Standard deviation of the x-coordinate = 5.508

 =Standard deviation of the y-coordinate = ?=k

Slope of line is given by formula

If slope of line is m, then

m =

m=

Substitute the value of k, i.e Standard deviation of the y-coordinate and then you can get the slope of line to three decimal places.

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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