What is the solution to the system of linear equations? {2x+4y=203x+2y=26 enter your answer in the boxes. ([],[])

{x = 8 ,  y = 1

Step-by-step explanation:

Solve the following system:

{2 x + 4 y = 20 | (equation 1)

{3 x + 2 y = 26 | (equation 2)

Swap equation 1 with equation 2:

{3 x + 2 y = 26 | (equation 1)

{2 x + 4 y = 20 | (equation 2)

Subtract 2/3 × (equation 1) from equation 2:

{3 x + 2 y = 26 | (equation 1)

{0 x+(8 y)/3 = 8/3 | (equation 2)

Multiply equation 2 by 3/8:

{3 x + 2 y = 26 | (equation 1)

{0 x+y = 1 | (equation 2)

Subtract 2 × (equation 2) from equation 1:

{3 x+0 y = 24 | (equation 1)

{0 x+y = 1 | (equation 2)

Divide equation 1 by 3:

{x+0 y = 8 | (equation 1)

{0 x+y = 1 | (equation 2)

Collect results:

 {x = 8 ,  y = 1

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing im pretty sure that is the right answer

step-by-step explanation:

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step-by-step explanation:

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