What is the equation of a line ,in standard form that passes through (4, -3) and is parallel to the line whose equations is 4x+y-2=04x-y=134x+y=134x+y=-13

4x + y = 13

Step-by-step explanation:

1.  Change 4x + y -2=0 into slope intercept form to find the slope:

     y = -4x +2   The slope is -4

2.  Plug in x, y and m into y = mx + b

    -3 = -4 (4) + b

    -3 = -16 + b

     13 + b

3.  Plug m and b into equation y = mx + b

     y = -4x + 13

4.  Change equation into standard form:

     4x - y = 13

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

20

step-by-step explanation: