Pls the figure shows two parallel lines ab and de cut by the transversals ae and bd: which statement best explains the relationship between triangle abc and triangle edc ? a. triangle abc is similar to triangle edc , because m∠3 = m∠6 and m∠1 = m∠4 b. triangle abc is similar to triangle edc , because m∠3 = m∠4 and m∠1 = m∠5 c. triangle abc is congruent to triangle edc , because m∠3 = m∠4 and m∠1 = m∠5 d. triangle abc is congruent to triangle edc, because m∠3 = m∠6 and m∠61 = m∠4

Option B is correct.

Step-by-step explanation:

We have given a triangle ABC and EDC please look at the figure

We can see that AE and BD are transversal therefore, ∠EAB=∠AED being alternate interior angles

And ∠ACB=∠DCE are vertically opposite angles hence, equal

So, by AA similarity postulate the above to triangles are similar

ΔABC ΔEDC

Therefore, Option B is correct that is Triangle ABC is similar to triangle EDC , because m∠3 = m∠4 and m∠1 = m∠5

NOTE: m∠3 = m∠4 corresponds to m∠ACB=m∠DCE

And m∠1 = m∠5 corresponds to m∠EAB=m∠AED

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.

22 dimes and 9 nickels

step-by-step explanation: