You research the cost of a gallon of gasoline over several years to look for a trend. the table shows your data. the line of best fit uses years since 1980 as the input value. what is a line of best fit for the data? based upon these prices, how much would you expect to pay in 2028? year: 1980, 1984, 1988, 1992, 1996, 2000, 2004, 2008, 2012 price/gallon: $1.25, $1.27, $1.05, $1.28, $1.43, $1.68, $2.11, $3.72, $3.99 a.) y= 0.087x+2.26; $6.44 b.) y= 0.087x+0.587; $4.76 c.) y= 0.134x+1.25; $7.68 d.) y= 0.0347x+0.856; $2.52

B.) y= 0.087x+0.587; $4.76

Without doing a lot of work, you can weed out the answer choices that don't make any sense.

The approximately $2.75 rise in price in 32 years is about $0.90 per year (to 1 significant digit), so rules out answer choices C and D.

The low-end prices near $1 rule out answer choice A, which has a y-interecept well above the $1 range. That leaves answer choice B.

_____

If you go to the trouble to enter the data into a calculator and have it give you the line of best fit, you find it is about ...

... y = 0.867917x +0.586889 . . . . . matches selection B

and this equation gives you a value for x=48 (year 2028) that is $4.75. Rounding the equation coefficients before you use them will give a different value for the year 2028.

47

step-by-step explanation:

spinning a 1, 2, or 3. option d.

step-by-step explanation: when spinning a number graph up to 4, and aiming for any number less than 3, that automatically eliminates the number 4. now you have two numbers to spin on that are less than 3, but the number 3 is included in this question because it's no greater of an number than itself. i hope this you : )