Judy is now twice as old as adam, but 6 years ago, she was 5 times as old as he was. how old is judy now? plz bros.

Judy is 16 years old

Step-by-step explanation:

J = Judy's age

A = Adams age

J = 2A

Six years ago   (subtract 6 from the ages)

(J-6) = 5*(A-6)

Distribute

J-6 = 5A - 30

Substitute J = 2A

2A -6 = 5A -30

Subtract 2A from both sides

2A-2A -6 = 5A-2A -30

-6 = 3A -30

Add 30 to each side

-6+30 = 3A-30+30

24 = 3A

Divide by 3

24/3 = 3A/3

8 = A

Adam is 8 years old now

We need to find Judy's age

J = 2A

J = 2*8

J = 16

Judy is 16 years old

answer: the answer to your question is parallel

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!