Mo’s farm stand sold a total of 165 pounds of apples and peaches. she sold apples for 1.75 per pound and peaches for 2.50 per pound. if she makes $337.50 how many pounds of peaches did she sell?

She sold 65 pounds of peaches to make $337.50 .

Step-by-step explanation:

Given :

Mo’s Farm stand sold a total of 165 pounds of apples and peaches.

She sold apples for 1.75 per pound and peaches for 2.50 per pound.

She made $337.50.

To Find : If she makes $337.50 how many pounds of peaches did she sell?

Solution :

Let She sold x pounds of apples.

Let She sold y pounds of peaches .

Since we are given that she old a total of 165 pounds of apples and peaches.

⇒      ----(A)

Now , cost of 1 pound of apples = $1.75

So, cost of x pounds of apples = $1.75 x .

Now , cost of 1 pound of peaches  = $2.50

So, cost of y pounds of peaches = $2.50 y .

Since she made $337.50

⇒$1.75 x + $2.50 y  = $337.50   ---(B)

Now solve (A) and (B) using substitution method

Substitute values of x from (A) in (B)

⇒1.75 (165-y)+2.50y  = 337.50

⇒288.75 - 1.75 y +2.50 y = 337.50

⇒288.75 + 0.75 y = 337.50

⇒0.75 y = 337.50 - 288.75

⇒0.75 y = 48.75

⇒ y = 48.75/0.75

⇒y = 65

Thus , She sold 'y' 65 pounds of peaches .

To calculate value of x put this value of y in (A)

⇒x + 65 = 165

⇒ x = 165-65

⇒x = 100

Thus , She sold 'x' 100 pounds of apples

Hence , she sold 65 pounds of peaches to make $337.50 .

i dont get the question

step-by-step explanation:

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf = 

pf = 6,25 u

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step-by-step explanation: