Solve for x (3x-+3)-0 smaller x=? larger x=?

x=2  and x=3

Step-by-step explanation:

(3x-6)(-x+3)=0

We can use the zero product property to solve for x

3x-6 = 0 and -x+3 =0

3x-6 = 0

Add 6 to each side

3x-6+6 = 6

3x=6

Divide by 3

3x/3 =6/3

x =2

-x+3 =0

Add x to each side

-x+x+3 = +x

3 =x

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15