How much pizza sauce is need to cover a 16" pizza? (16" is the diameter of the pizza)

Approximately 201.06 in² of pizza sauce is needed

(if using the approximation π ≈ 3.14, then the answer is 200.96 in²)

Step-by-step explanation:

We assume that the pizza is perfectly circular and that we want to cover the entire surface. We need the formula for the surface area of a circle which is

  A = πr²,

where r is the radius of the pizza.

By definition, the diameter is twice the radius. So the radius of this pizza is half of 16'' = 16 inches, which is 8 in.

Therefore, (using a calculator value for π instead of 3.14 approximation),

  A = π(8 in)² = 64π in² ≈ 201.06 in².

Approximately 201.06 in² of pizza sauce is needed.

If you are need to use the approximation π ≈ 3.14, then the answer is 200.96 in²

201.06 square inches

Step-by-step explanation:

We need to cover the whole surface area of the pizza so if the pizza is a circular one (using the typical shape), then we can use the formula of the area of a circle.

Area of a circle = pi * r^2

We are given the diameter of the circle to be 16 inches so its radius will be 8 inches.

Substituting this value of radius in the formula to get:

= =

Therefore, about 201.06 square inches of pizza sause is needed to cover the pizza.

i need more info. are you looked to see there mph? how much they deliver? how far they go?

step-by-step explanation:

a.   we have two

lines:   y = 4-x   and  

y = 8-x^-1

given two simultaneous equations that are both to be

true, then the solution is the points where the lines cross. the intersection is

where the two equations are equal. therefore the solution that works for both

equations is when

4-x = 8-x^-1

this is where the two lines will cross and that is the

common point that satisfies both equations.

b.   4-x = 8-x^-1

  x           4-x       8-x^-1

-3           7        

8.33

-2           6         8.5

-1           5         9

  0           4        

-

  1           3        

7

  2           2        

7.5

  3           1         7.67

the table shows that none of the x values from -3 to 3 is

the solution because in no case does

4-x = 8-x^-1

to find the solution we need to rearrange the equation to

find for x:

4-x = 8-x^-1

multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

therefore there are two points that satisfies the

equation.

find y:  

x=-4.236

y = 4-x   = 4 – (-4.236)

= 8.236

y = 8-x^-1 =   .236)^-1

= 8.236

x=0.236

  y = 4-x   = 4 – (0.236) = 3.764

y = 8-x^-1 =   8-(0.236)^-1

= 3.764

thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

c.   to solve

graphically the equation 4-x = 8-x^-1

we would graph both lines: y = 4-x   and   y

= 8-x^-1

the point on the graph where the lines cross is the

solution to the system of equations.

just graph the points on part b on a cartesian coordinate

system and extend the two lines.   the

solution is, as stated, the point where the two lines cross on the graph.

step-by-step explanation:

mark brainliest!