Type the correct answer in each box. use numerals instead of words. if necessary, use / for the fraction bar(s).
find the inverse of the given function.
27pionts

Step-by-step explanation:

1. When you replace f(x) by x and x by y, you have

... x = 2^y + 6

The first thing you do is subtract 6; then you take the base-2 logarithm:

... (x -6) = 2^y

... log2(x -6) = y = f^-1(x)

You know that to get the y-term by itself, you must subtract 6. Anything else you do will operate on (x-6). Only answer choice D has that sort of construction.

2. When you swap x and y and solve for y, you have ...

... x = -1/2√(y+3)

... -2x = √(y +3) . . . . . . multiply by -2

... (-2x)^2 = y +3 . . . . . square

... 4x^2 - 3 = y = f^-1(x) . . . . subtract 3

The range of f(x) is (-∞, 0], so that is the domain of f^-1(x). That is, f^-1(x) is defined for x ≤ 0.

3. The product of the two functions is ...

... (x -6)(√x)(x +3) = (√x)(x^2 -3x -18)

Every term will have a factor of √x, and the coefficients will be 1, -3, -18. Only selection B matches those conditions.

Question One: log_2(x - 6) = y

Question Two: First blank: 4 Second blank 0

Question Three: B

Step-by-step explanation:

f(x) = 2^x + 6

y = 2^x + 6                 Interchange the x and y

x = 2^y + 6                Subtract 6 from both sides

x - 6 = 2^y                 Take the log of both sides

log(x - 6) = log 2^y    The power can be multiplied by the log of 2

log(x - 6) = y log(2)    Divide by the log of 2

log(x - 6)/log(2) = y    This to me is the preferred answer. It allows you to calculate what the actual number is or graph it on Desmos

The answer I have given is equivalent to using base 2 as your log, but calculating that is not always easy.

log_2(x - 6) = y

D

Problem Two

You want the inverse of y = - 1/2 sqrt(x + 3)   x ≥ - 3

Note: you cannot have any number less than -3 because if you do, you will be taking the square root of -x which involves complex numbers. In addition x ≥ -3 is a domain. You have to keep that in mind when doing this question.

The domain and range of this is a little harder to figure out. The range of f(x) becomes the domain of f-1(x)

The range of f(x) is 0 <=y < - infinity

So the domain of f-1(x) <= 0

The first blank is 4 and the second one is 0

Graph: the graph is given you below the question. What it shows is the f(x) and f^-1(x) are symmetrical about y = x. Most inverses are. If you want to check your work, it is best to include a graph when doing inverses.

Problem Three

The best way to begin this problem is to apply the associative property of multiplication and start by rewriting the givens as x^(1/2)[(x - 6)(x + 3)]. Do what is in the square brackets first.

Now deal with the x^(1/2) which must be multiplied by all three terms in the square brackets.

Result: x^(5/2) - 3x^(3/2) - 18x^(1/2)

√(x^5) - 3√x^3 - 18√x

B

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step-by-step explanation:

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step-by-step explanation:

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