Robin is standing on the top of a 40-foot flagpole at 1 p. m. at the same time, a 4-foot child on the ground casts a shadow of length 0.8 feet. if robin is 6 feet tall, how much longer is the shadow of the flagpole and robin together than the shadow of the flagpole alone? specify your answer as a decimal to the nearest tenth.

1.2 ft

Step-by-step explanation:

We can use ratio's to solve this problem.  Put the item on top, and the shadow on the bottom

40 ft flagpole       4 ft child

=

x ft shadow            .8 ft shadow

Using cross products

40 * .8 = 4x

32 = 4x

Divide each side by 4

32/4 = 4x/4

8 = x

The flag pole casts an 8 ft shadow

The question asks how much longer is the shadow of the flagpole and Robin than the flagpole?  In other words, how long is Robins shadow

40 ft flagpole       6ft  Robin

=

8 ft shadow            x ft shadow

Using cross products

40 *x = 6*8

40x = 48

Divide by 40

40x/40 = 48/40

x = 1.2

i think its a and d

step-by-step explanation:

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w