Astudent took a system of equations, multiplied the first equation by and the second equation by , then added the results together. based on this, she concluded that there were no solutions. which system of equations could she have started with? a. -2x+4y=4-3x+6y=6b.3x+y=12-3x+6y=6c. 3x+6y=9-2x-4y=4d. 2x-4y=6-3x+6y=9

option A

-2x + 4y = 4

-3x + 6y = 6

Step-by-step explanation:

In option A, if the student multiply the first equation by 3 and the second equation by -2, then the equations become

-6x+12y = 12 and

6x-12y =-12

If she adds both equations, she will get 0 = 0

This means that the system has infinite number of solutions.

Hence, the student could have started with equations -2x + 4y = 4 and -3x + 6y = 6.

the answer to this question is 3/19

step-by-step explanation: