4z 27 +x5 y14 if x, y and z each represent a different digit from 0 to 9, what is the value of (x)(y)(z)?

4(1)(2) = 8

Step-by-step explanation:

Consider the addition in the unit digits.

z +7 + 5 = z + 12

and the unit digit of this sum should be 4 since the unit digit of the answer is 4.

Also, since z is a number from 0 to 9, the only possibility is z = 2.

Hence, the unit digit sum is 14 and the carry over is 1.

Now, consider the tenth digits sum with previous carry over 1.

1 + 4 + 2 + x = y1

7 + x = y1

Since, x and y are numbers from 0 to 9, the only possibility is x = 4 and hence

7 + 4 = y1

11 = y1

y = 1

So, x = 4, y = 1, z = 2

(x)(y)(z) = (4)(1)(2) = 8