Ared die is tossed and then a green die is tossed. what is the probability that the red die shows a number larger than three or the green die shows a number less than three?

5/6

Step-by-step explanation:

I'm gonna set up some notation here. I'll use R# to indicate a red die with some number # on it (e.g. R2 for a 2 on the red die, R1 for a 1), and G# for the green die. Since the red die is limited to numbers greater than 3, we can only have the possibilities R4, R5, and R6. The green die is even more limited, with only the possible outcomes G2 and G1.

When we find the probability of this outcome OR the other, we add together their individual probabilities. R4, R5, and R6 represent 3 out of 6 possible rolls for the red die, so the probability of rolling one is 3/6. For the green die, G2 and G1 represent 2 out of 6 possible rolls, giving a probability of 2/6. Adding these two probabilities together, we find that the probability of meeting one of the provided criteria or the other is 3/6 + 2/6 = 5/6.

omg what happend to your question? if you could edit this question i can

step-by-step explanation:

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: