∆abc rotates around point d to create ∆a′b′c′. based on the position of , shown in the figure, the coordinates of a′ are . if ∆a′b′c′ rotates 90° counterclockwise around point e(7, 5) to form triangle ∆a″b″c″, the coordinates of a″ are

The coordinates of A' are (4,1). Therefore the coordinates of A'' are (11,2).

Step-by-step explanation:

From the figure it is clear that the coordinates of triangle ABC are A(4,9), B(4,6) and C(2,6).

The ∆ABC rotates around point D to create ∆A′B′C′. The vertices of image are  B'(4,4) and C'(6,4).

From the figure it is clear that ∆ABC rotates 180° around point D to create ∆A′B′C′.

The coordinates of A' are

The coordinates of A' are (4,1).

If ∆A′B′C′ rotates 90° counterclockwise around point E(7, 5) to form triangle ∆A″B″C″, then

The coordinates of A'' are

Therefore the coordinates of A'' are (11,2).

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1