1.) there are 16 juniors and 8 seniors in the chess club. if the club members decide to send 9 juniors to a tournament, how many different possibilities are there? 2.) how many different ways can 3 cards be drawn from a deck of 52 cards without replacement? 3.) how many different ways can 3 cards be drawn from a deck of 52 cards with replacement? 4.) a corporation has 5 officers to choose from which 3 are selected to comprise the board of directors. how many combinations are there? 5.) a combination lock has the numbers 1 to 40 on each of three consecutive tumblers. what is the probability of opening the lock in ten tries?

1.) There are 16 juniors and 8 seniors in the Chess Club. If the club  members decide to send 9 juniors to a tournament, how many different  possibilities are there?  

(16 over 9) = 16!/(9!*7!) = 11440

2.) How many different ways can 3 cards be drawn from a deck of 52  cards without replacement?  

52*51*50 = 132600

3.) How many different ways can 3 cards be drawn from a deck of 52  cards with replacement?  

52^3 = 140608

4.) A corporation has 5 officers to choose from which 3 are selected  to comprise the board of directors. How many combinations are there?

(5 over 3) = 5!/(3! * 2!) = 10

5.) A combination lock has the numbers 1 to 40 on each of three  consecutive tumblers. What is the probability of opening the lock in  ten tries?

10/40^3 = 1/6400

3

step-by-step explanation:

in standard form:

a= dictionaries

b= maps

you have to buy 3 dictionaries, so put a 3 next to the a (dictionaries) so that you can multiply them by each other.

a3+b= 60 (the amount of money you have)

we already know the cost of a=15 so replace a with $15

($15 x 3)+b=60

multiply 15 and 3 to get $45 and replace it with $45

45+b=60

and then replace b with 15 to get the total:

45+15=60

that means you have $15 left after buying 3 dictionaries.

15 divided by the cost of a map ($5) equals 3.

so you can buy 3 maps.

sorry if it was confusing!