Threeangles of a quadrilateral are equal and its fourth angel is 120° . find all the angels

80°

Step-by-step explanation:

Three angles are equal

Let the equal angle be x

3x+120=360

3x=240

x=240/3

=80

Hence the three angles are 80∘

Each of the three congruent angles has measure 80 deg. The fourth angle has measure 120 deg.

Step-by-step explanation:

The sum of the measures of the angles of an n-sided polygon is (n - 2)180.

A quadrilateral has 4 sides, so n = 4 in the formula above.

(n - 2)180 = (4 - 2)180 = 2(180) = 360

The sum of the measures of the angles of a quadrilateral is 360 degrees.

Three angles are congruent. Let the measures of the three congruent angles be x. The sum of the measures of the 3 angles is x + x + x = 3x.

The sum of the measures of the angles is 360 deg.

3x + 120 = 360

Subtract 120 from both sides.

3x = 240

Divide both sides by 3.

x = 80

Each of the three congruent angles has measure 80 deg. The fourth angle has measure 120 deg.

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~