If the domain of f (x ) = 4 +x2 is {-1, 0, 1, 2}, what is the range?

y = {5, 4, 8}

Step-by-step explanation:

f(x) = 4 + x²

f(-1) = 4 + (-1)²

      = 4 + 1

      = 5

f(0) = 4 + (0)²

      = 4 + 0

      = 4

f(1) = 4 + (1)²

      = 4 + 1

      = 5

f(2) = 4 + (2)²

      = 4 + 4

      = 8

Put the values from domain to the equation of the function.

f(x) = 4 + x²

f(-1) = 4 + (-1)² = 4 + 1 = 5

f(0) = 4 + 0² = 4 + 0 = 4

f(1) = 4 + 1² = 4 + 1 = 5

f(2) = 4 + 2² = 4 + 4 = 8

3< x< 5

step-by-step explanation:

|x - 4| < 1

there are two solutions, one positive and one negative.   remember to flip the inequality when taking the negative solution

x-4 < 1       x-4 > -1

add 4 to each side

x-4+4 < 1+4       x-4+4 > -1+4

x< 5                 x> 3

3< x< 5

answer: a

step-by-step explanation: