Problem 3 among the cast aluminum parts manufactured on a certain day, 80% were flawless, 15% had only minor flaws, and 5% had major flaws. find the probability that a randomly chosen part a. has a flaw (major and minor). b. has no major flaws.

A) P(flaw) = 0.2

B) P(No major flaws) = 0.95

Step-by-step explanation:

To find the probability of flaws, we can find the probability of no flaws first by dividing by 100:

P(no flaw) = = 0.8

So then:

P(flaw) = 1 - P(no flaw) = 1 - 0.8 = 0.2

P(flaw) = 0.2

First, we need to find the probability of major flaws:

P(major flaws) =

P(Major flaws) = 0.05

So to find the probability of no major flaws:

P(No major flaws) = 1 - P(major flaws) = 1 - 0.05 = 0.95

P(No major flaws) = 0.95

70,000 + 6,000 + 800 + 30

step-by-step explanation:

days of the week

step-by-step explanation:

javier earned more money then kyle, so that won't always be a constant term, but the days of the week do not change so that term is always constant.

edit: i meant