Given a standard deck of playing cards, what is the probability of randomly selecting a card that is either red or a face card or both? (a standard deck of playing cards has 52 cards, divided equally between red cards and black cards. there are twelve face cards among these 52, which are also divided equally between red cards and black cards. no card may be both red and black.)

Step-by-step explanation:

Red   or    Face   -  duplicates (both red & face)

    +            -    

=

=   simplified

amount of oatypop that contains the prize = 40%

amount   of oatypop which doesn't contain the prize = (100-40)=60%

probability that hannah will win a prize

    = s +f s +f f s+ff   f s+ff f f s+ infinity.where f= failure,s= success

=   or 60%

probability that hannah only has to buy 3 or less boxes before getting a prize= (s) and ( f s) and (ff s) and (f f f s)

        = = 87.04 %  

step-by-step explanation:

4

step-by-step explanation:

6 (donuts) divided by 3 is 2.

so 2/3 means 2 times 2, which is 4/6.

you get two and your friend gets four.