Abag contains 6 blue marbles 10 red marbles and 9 green marbles. if 2 marbles are drawn at random without replacement what is the probability that to green marbles are drawn

P(1 and 2 are green) = 3/25

Step-by-step explanation:

We need to know the total number of marbles

6 Blue + 10 red + 9 green = 25 marbles

P ( 1st marble is green) = green/ total

                                       = 9/25

Since we don't put it back, there are  

6 Blue + 10 red + 8 green = 24 marbles

P ( 2st marble is green) = green/ total

                                       = 8/24  = 1/3

P(1 and 2 are green) = P(1st green) * P(2nd green)

                                  = 9/25 * 1/3

                                   = 3/25

answer: hello!

the answer to this problem is, d. (7.3)(8.52)=62.19