What is the remainder when (2x^3 + 4x^2 - 32x - 40) divided by (x - 4) a. 2 b. 24 c. 96 d. 100

The answer is B.

Step-by-step explanation:

2(4)^3 + 4(4)^2 - 32(4) - 40

2(64) + 4(16) - 32(4) - 40

128 + 64 - 128 - 40

24

I hope this helps!

Cheers, July.

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐