Which of the following expressions is equal to 2x^(2)+8? (2x-4i)(x-2i) (2x-4i)(x-2i) (2x+4i)(x+2i) (2x_2i)(x+6i)

The expression equal to 2x^(2)+8 is:

First option (2x-4i)(x+2i)

Step-by-step explanation:

If we multiply

(2x-4i)(x+2i)=(2x)(x)+(2x)(2i)-(4i)(x)-4i(2i)

(2x-4i)(x+2i)=2x^(1+1)+4xi-4xi-8i^(1+1)

Simplifying:

(2x-4i)(x+2i)=2x^2-8i^2

and i^2=-1, then:

(2x-4i)(x+2i)=2x^2-8(-1)

Multiplying:

(2x-4i)(x+2i)=2x^2+8

show us the graphs dude

step-by-step explanation:

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)