If f(×)=2x^2-5 and g(×)=3×+3 find (f-g)(×)a.3x-2x^2-2b.2x^2-3x-2 c.-x^2-7d.2x^2-3x-8

d.  2x^2    -3x  -8

Step-by-step explanation:

if f(×)=2x^2-5 and

g(×)=3×+3

(f-g)(×)=

I like to line them up vertically

2x^2-5

-(3x+3)

Distribute the minus sign

2x^2-5

-3x-3

Line up the powers

2x^2+ 0x   -5

           -3x-3

2x^2    -3x  -8

3x^3-x^2+6x-9

ian gone lie this got me confused

step-by-step explanation: