Anyone know the answer ! write the standard form of the equation of a line with a slope of -4 passing through the point (1, -4).

The equation of this line would be 4x + y = 0

Step-by-step explanation:

We can use this slope along with the point in point-slope form to find the equation of the line. We simply need to take the base form, plug in the known values and then solve for the constant.

y - y1 = m(x - x1)

y + 4 = -4(x - 1)

y + 4 = -4x + 4

4x + y + 4 = 4

4x + y = 0

a4 - 3a2 - 1

step-by-step explanation:

step   1   :

equation at the end of step   1   :

  ((a4) -   3a2) -   1

step   2   :

trying to factor by splitting the middle term

2.1     factoring   a4-3a2-1  

the first term is,   a4   its coefficient is   1 .

the middle term is,   -3a2   its coefficient is   -3 .

the last term, "the constant", is   -1  

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068