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Consider the proof. given: segment ab is parallel to line de. prove: what is the missing statement in step 5?

Given: ae ≅ ce ; de ≅ be prove: abcd is a parallelogram. we have that ab || dc. by a similar argument used to prove that △aeb ≅ △ced, we can show that △ ≅ △ceb by. so, ∠cad ≅ ∠ by cpctc. therefore, ad || bc by the converse of the theorem. since both pair of opposite sides are parallel, quadrilateral abcd is a parallelogram.

Find │–14│ a. 14 b. –14 c. start fraction 1 over 14 end fraction