Adult tickets to the fall play cost $8 and student tickets cost $4. the drama calss sold 20 more adult tickets than student tickets to the fall play. if the class collected $880 from ticket sales, how many adult tickets were sold?

80 adult tickets were sold

Step-by-step explanation:

If you subtract the extra 20 adult tickets from ticket numbers and revenue, you get ...

equal numbers of $4 and $8 tickets were sold for a total of $720 collected

Since that is some number of ticket pairs worth $12 per pair, there must have been ...

$720/12 = 60 pairs of $4 and $8 tickets

The number of adult tickets is 20 more than this, so is

60 + 20 = 80 . . . . adult tickets sold

If you feel better with an equation, rather than numerical reasoning, you can let n represent the number of adult tickets. Then n-20 is the number of student tickets and total revenue is ...

8n +4(n-20) = 880

12n -80 = 880 . . . . . simplify

12n = 960 . . . . . . . . . add 80

n = 80 . . . . . . . . . . . . divide by 12

Comment on the different solutions

Using n for the number of adult tickets, we effectively chose a scenario where we added 20 student tickets to bring the total to $960 for some number of $12 pairs of tickets. That number is 80, the number of adult tickets.

In the "word solution" given at first, we effectively solved for the number of student tickets, then added 20 to get the number of adult tickets. The corresponding equation would be ...

4s +8(s+20) = 880 . . . s = number of student tickets sold

12s = 720 . . . . . . . . . subtract 160, the price of the 20 extra adult tickets

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!