Find the consecutive odd integers that have a sum of 9. order them from least to greatest

Hello from MrBillDoesMath!

No solution is possible using odd consecutive integer

Discussion:

Let "n" be the smaller odd integer. Then

n + (n+2) = 9 =>

2n + 2 = 9 =>

2n = 7 =>    Oops!  2n is an even integer; 7 is odd. NO integer solution exists

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MrB

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option c) graph of line going through 1, 4 and 3, 10

step-by-step explanation:

let y equal to margo's coin collection

let x equal to number of years

at the begining x=0, y=1 → point=(x,y)→point=(0,1)

she adds 3 coins per year, then y=1+3x

at x=1, y=1+3(1)=1+3→y=4→point=(x,y)→point=(1,4)

at x=3, y=1+3(3)=1+9→y=10→point=(x,y)→point=(3,10)

the graph of line going through (1, 4) and (3, 10), then the option c is the correct.

1,8,15,22,29,36,43,50

step-by-step explanation: